A bar magnet of magnetic moment M1 is axially cut into two equal parts. If these two pieces are arranged perpendicular to each other, the resultant magnetic moment is M2 . Then the value of M1/M2 is

Question

A bar magnet of magnetic moment M1 is axially cut into two equal parts. If these two pieces are arranged perpendicular to each other, the resultant magnetic moment is M2 . Then the value of M1/M2 is (A)  (1/2√2)  (B)  1  (C)  (1/√2)  (D)  √2

Tardigrade Admin · Accepted Answer

When magnet is cut axially, new magnetic moment of each part M1=((M/2)) l=(M/2) On placing both the parts perpendicularly. M2=√(M')2+(M')2=(M/√2) ∴ (M1/M2)=√2

Q. A bar magnet of magnetic moment $M_{1}$ is axially cut into two equal parts. If these two pieces are arranged perpendicular to each other, the resultant magnetic moment is $M_{2}$ . Then the value of $M_{1} / M_{2}$ is

$\frac{1}{2 2}$

$1$

$\frac{1}{2}$

$2$

When magnet is cut axially, new magnetic moment of each part
$M_{1} = (\frac{M}{2}) l = \frac{M}{2}$
On placing both the parts perpendicularly.
$M_{2} = (M^{'})^{2} + (M^{'})^{2} = \frac{M}{2}$
$∴ \frac{M _{1}}{M _{2}} = 2$

Q. A bar magnet of magnetic moment M1​ is axially cut into two equal parts. If these two pieces are arranged perpendicular to each other, the resultant magnetic moment is M2​ . Then the value of M1​/M2​ is

22​1​

1

2​1​

2​

When magnet is cut axially, new magnetic moment of each part M1​=(2M​)l=2M​ On placing both the parts perpendicularly. M2​=(M′)2+(M′)2​=2​M​ ∴M2​M1​​=2​

Q. A bar magnet of magnetic moment $M_{1}$ is axially cut into two equal parts. If these two pieces are arranged perpendicular to each other, the resultant magnetic moment is $M_{2}$ . Then the value of $M_{1} / M_{2}$ is

$\frac{1}{2 2}$

$1$

$\frac{1}{2}$

$2$

When magnet is cut axially, new magnetic moment of each part
$M_{1} = (\frac{M}{2}) l = \frac{M}{2}$
On placing both the parts perpendicularly.
$M_{2} = (M^{'})^{2} + (M^{'})^{2} = \frac{M}{2}$
$∴ \frac{M _{1}}{M _{2}} = 2$