A balloon is filled with 2L air in Kota where temperature is 27° C . What will be the volume of the balloon when it is carried to Shimla where temperature is 0° C.? (Assume atmospheric pressure is same) :-

Question

A balloon is filled with 2L air in Kota where temperature is 27° C . What will be the volume of the balloon when it is carried to Shimla where temperature is 0° C.? (Assume atmospheric pressure is same) :- (A) 0 L (B) 2 L (C) 0.55 L (D) 1.82 L

Tardigrade Admin · Accepted Answer

constant pressure (V2/V1)=(T2/T1) (V2/2)=(273/300)⇒ V2=1.82 L

Q. A balloon is filled with $2 L$ air in Kota where temperature is $2 7^{\circ} C$ . What will be the volume of the balloon when it is carried to Shimla where temperature is $0^{\circ} C . ?$ (Assume atmospheric pressure is same) :-

0 L

2 L

0.55 L

1.82 L

constant pressure
$\frac{V _{2}}{V _{1}} = \frac{T _{2}}{T _{1}}$
$\frac{V _{2}}{2} = \frac{273}{300} \Rightarrow V_{2} = 1.82 L$

Q. A balloon is filled with 2L air in Kota where temperature is 27∘C . What will be the volume of the balloon when it is carried to Shimla where temperature is 0∘C.? (Assume atmospheric pressure is same) :-

0 L

2 L

0.55 L

1.82 L

constant pressure V1​V2​​=T1​T2​​ 2V2​​=300273​⇒V2​=1.82L

Q. A balloon is filled with $2 L$ air in Kota where temperature is $2 7^{\circ} C$ . What will be the volume of the balloon when it is carried to Shimla where temperature is $0^{\circ} C . ?$ (Assume atmospheric pressure is same) :-

constant pressure
$\frac{V _{2}}{V _{1}} = \frac{T _{2}}{T _{1}}$
$\frac{V _{2}}{2} = \frac{273}{300} \Rightarrow V_{2} = 1.82 L$