A balloon has 2 g of air. A small hole is pierced into it. The air comes out with a velocity of 4 m / s. If the balloon shrinks completely in 2.5 s. The average force acting on the balloon is

Question

A balloon has 2 g of air. A small hole is pierced into it. The air comes out with a velocity of 4 m / s. If the balloon shrinks completely in 2.5 s. The average force acting on the balloon is (A) 0.008 N (B) 0.0032 N (C) 8 N (D) 3.2 N

Tardigrade Admin · Accepted Answer

F =(v d m/d t) =4((2/1000 × 2.5)) =0.0032 N

Q. A balloon has $2 g$ of air. A small hole is pierced into it. The air comes out with a velocity of $4 m / s$ . If the balloon shrinks completely in $2.5 s$ . The average force acting on the balloon is

0.008 N

0.0032 N

8 N

3.2 N

$F = \frac{v d m}{d t}$
$= 4 (\frac{2}{1000 \times 2.5})$
$= 0.0032 N$

Q. A balloon has 2g of air. A small hole is pierced into it. The air comes out with a velocity of 4m/s. If the balloon shrinks completely in 2.5s. The average force acting on the balloon is

0.008 N

0.0032 N

8 N

3.2 N

F=dtvdm​ =4(1000×2.52​) =0.0032N

Q. A balloon has $2 g$ of air. A small hole is pierced into it. The air comes out with a velocity of $4 m / s$ . If the balloon shrinks completely in $2.5 s$ . The average force acting on the balloon is

$F = \frac{v d m}{d t}$
$= 4 (\frac{2}{1000 \times 2.5})$
$= 0.0032 N$