A ball of mass 10 g moving perpendicular to the plane of the wall strikes it and rebounds in the same line with the same velocity. If the impulse experienced by the wall is 0.54 Ns, the velocity of the ball is

Question

A ball of mass 10 g moving perpendicular to the plane of the wall strikes it and rebounds in the same line with the same velocity. If the impulse experienced by the wall is 0.54 Ns, the velocity of the ball is (A) 27 ms-1 (B) 3.7 ms-1 (C) 54 ms-1 (D) 37 ms-1

Tardigrade Admin · Accepted Answer

Given, Δ p =0.54 N - s m =10 × 10-3 k .g Impulse Δ p =m v-(-m v) Δ p =2 m v 0.54 =2 × 10 × 10-3 × v V =(0.54/2 × 10-2) ⇒ V =(54/2) V =27 m / s

Q. A ball of mass $10 g$ moving perpendicular to the plane of the wall strikes it and rebounds in the same line with the same velocity. If the impulse experienced by the wall is $0.54 N s$ , the velocity of the ball is

$27 m s^{- 1}$

$3.7 m s^{- 1}$

$54 m s^{- 1}$

$37 m s^{- 1}$

$5.4 m s^{- 1}$

Given,
$Δ p = 0.54 N - s$
$m = 10 \times 1 0^{- 3} k . g$
Impulse $Δ p = m v - (- m v)$
$Δ p = 2 m v$
$0.54 = 2 \times 10 \times 1 0^{- 3} \times v$
$V = \frac{0.54}{2 \times 1 0 ^{- 2}}$
$\Rightarrow V = \frac{54}{2}$
$V = 27 m / s$

Q. A ball of mass 10g moving perpendicular to the plane of the wall strikes it and rebounds in the same line with the same velocity. If the impulse experienced by the wall is 0.54Ns, the velocity of the ball is

27ms−1

3.7ms−1

54ms−1

37ms−1

5.4ms−1

Given, Δp=0.54N−s m=10×10−3k.g Impulse Δp=mv−(−mv) Δp=2mv 0.54=2×10×10−3×v V=2×10−20.54​ ⇒V=254​ V=27m/s