Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
A ball of mass text0.2 kg moves with a velocity of 20ms- 1 and stops in 0.1s , then the force on the ball is
Q. A ball of mass
0.2
k
g
moves with a velocity of
20
m
s
−
1
and stops in
0.1
s
, then the force on the ball is
328
159
NTA Abhyas
NTA Abhyas 2022
Report Error
A
40
N
B
20
N
C
4
N
D
2
N
Solution:
Newton's second law states that the rate of change of momentum of a body is equal to the force applied.
So,
F
=
ma
=
Δ
t
m
Δ
v
⇒
F
=
0.1
0.2
×
20
=
40
N