A ball of mass text0.2 kg moves with a velocity of 20ms- 1 and stops in 0.1s , then the force on the ball is

Question

A ball of mass text0.2 kg moves with a velocity of 20ms- 1 and stops in 0.1s , then the force on the ball is (A) 40 N (B) 20 N (C) 4 N (D) 2 N

Tardigrade Admin · Accepted Answer

Newton's second law states that the rate of change of momentum of a body is equal to the force applied. So, F=ma=(m Δ v/Δ t) ⇒ F=(0 .2 × 20/0 .1)=40 N

Q. A ball of mass $0.2 k g$ moves with a velocity of $20 m s^{- 1}$ and stops in $0.1 s$ , then the force on the ball is

$40 N$

$20 N$

$4 N$

$2 N$

Newton's second law states that the rate of change of momentum of a body is equal to the force applied.
So, $F = ma = \frac{m Δ v}{Δ t}$
$\Rightarrow F = \frac{0.2 \times 20}{0.1} = 40 N$

Q. A ball of mass 0.2kg moves with a velocity of 20ms−1 and stops in 0.1s , then the force on the ball is

40N

20N

4N

2N