Thank you for reporting, we will resolve it shortly
Q.
A ball of mass $\text{0.2} \, kg$ moves with a velocity of $20ms^{- 1}$ and stops in $0.1s$ , then the force on the ball is
NTA AbhyasNTA Abhyas 2022
Solution:
Newton's second law states that the rate of change of momentum of a body is equal to the force applied.
So, $F=ma=\frac{m \Delta v}{\Delta t}$
$\Rightarrow F=\frac{0 .2 \times 20}{0 .1}=40 \, N$