A ball is thrown vertically downward with a velocity of 20m/s from the top of a tower. It hits the ground after some time with a velocity of 80m/s. The height of the tower is: (g = 10m/s2)

Question

A ball is thrown vertically downward with a velocity of 20m/s from the top of a tower. It hits the ground after some time with a velocity of 80m/s. The height of the tower is: (g = 10m/s2) (A) 360 m (B) 340 m (C) 320 m (D) 300 m

Tardigrade Admin · Accepted Answer

Using, v2=u2+2gh Given, V=80m/s and u=20 m/s h=(v2-u2/2g) =(6400-400/20) =300 m <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/470d43af009f769e9e1ad217f75107b6-.png" />

Q. A ball is thrown vertically downward with a velocity of 20m/s from the top of a tower. It hits the ground after some time with a velocity of 80m/s. The height of the tower is : (g = $10 m / s^{2}$ )

360 m

340 m

320 m

300 m

Using, $v^{2} = u^{2} + 2 g h$
Given, $V = 80 m / s$ and $u = 20 m / s$
$h = \frac{v ^{2} - u ^{2}}{2 g}$
$= \frac{6400 - 400}{20}$
$= 300 m$

Q. A ball is thrown vertically downward with a velocity of 20m/s from the top of a tower. It hits the ground after some time with a velocity of 80m/s. The height of the tower is : (g = 10m/s2)