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Q. A ball is thrown vertically downward with a velocity of 20m/s from the top of a tower. It hits the ground after some time with a velocity of 80m/s. The height of the tower is : (g = $10m/s^2$)

NEETNEET 2020Motion in a Straight Line

Solution:

Using, $v^{2}=u^{2}+2gh$
Given, $V=80m/s$ and $u=20 m/s$
$h=\frac{v^{2}-u^{2}}{2g}$
$=\frac{6400-400}{20}$
$=300\,m$
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