A ball is suspended by a thread from the ceiling of a tram car. The brakes are applied and the speed of the car changes uniformly from 36 Km h- 1 to zero in 5 s . The angle by which the ball deviates from the vertical is (g = 10 m s- 2)

Question

A ball is suspended by a thread from the ceiling of a tram car. The brakes are applied and the speed of the car changes uniformly from 36 Km h- 1 to zero in 5 s . The angle by which the ball deviates from the vertical is (g = 10 m s- 2) (A)  tan -1((1/3)) (B)  sin -1((1/5)) (C)  tan -1((1/5)) (D)  cot -1((1/3))

Tardigrade Admin · Accepted Answer

u=36kmh- 1=10ms- 1 v=u+at , tan θ =(a/g) v=10-a× 5(.given,v=0.) a = 2 tan θ =(2/10)

Q. A ball is suspended by a thread from the ceiling of a tram car. The brakes are applied and the speed of the car changes uniformly from $36 K m h^{- 1}$ to zero in $5 s$ . The angle by which the ball deviates from the vertical is $(g = 10 m s^{- 2})$

$tan^{- 1} (\frac{1}{3})$

$sin^{- 1} (\frac{1}{5})$

$tan^{- 1} (\frac{1}{5})$

$cot^{- 1} (\frac{1}{3})$

$u = 36 km h^{- 1} = 10 m s^{- 1}$ $v = u + a t$ , $t an θ = \frac{a}{g}$
$v = 10 - a \times 5 (g i v e n, v = 0)$
$a = 2$
$t an θ = \frac{2}{10}$

Q. A ball is suspended by a thread from the ceiling of a tram car. The brakes are applied and the speed of the car changes uniformly from 36Kmh−1 to zero in 5s . The angle by which the ball deviates from the vertical is (g=10ms−2)

tan−1(31​)

sin−1(51​)

tan−1(51​)

cot−1(31​)