A ball is projected horizontally with a velocity of 5 m/s from the top of a building 19.6 m high. How long will the ball take of hit the ground ?

Question

A ball is projected horizontally with a velocity of 5 m/s from the top of a building 19.6 m high. How long will the ball take of hit the ground ? (A) √2 s (B) 2 s (C) √3 s (D) 3 s

Tardigrade Admin · Accepted Answer

The time taken to hit the ground is given by <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/985adcef1f1be8b3cb6214d991bcf463-.png" /> T=√(2 H/g) =√(2 × 19.6/9.8)=2 s

Q. A ball is projected horizontally with a velocity of $5 m / s$ from the top of a building $19.6 m$ high. How long will the ball take of hit the ground ?

$2 s$

$2 s$

$3 s$

$3 s$

The time taken to hit the ground is given by

$T = \frac{2 H}{g}$
$= \frac{2 \times 19.6}{9.8} = 2 s$

Q. A ball is projected horizontally with a velocity of 5m/s from the top of a building 19.6m high. How long will the ball take of hit the ground ?

2​s

2s

3​s

3s

The time taken to hit the ground is given by T=g2H​​ =9.82×19.6​​=2s

Q. A ball is projected horizontally with a velocity of $5 m / s$ from the top of a building $19.6 m$ high. How long will the ball take of hit the ground ?

$2 s$

$2 s$

$3 s$

$3 s$

The time taken to hit the ground is given by

$T = \frac{2 H}{g}$
$= \frac{2 \times 19.6}{9.8} = 2 s$