Question

A ball is projected from point A with a velocity, $10m{s}^{-1}$ perpendicular to the inclined plane as shown in the figure. Range of the ball on the inclined plane is :

• A. $\frac{40}{3}m$
• B. $\frac{20}{13}m$
• C. $\frac{13}{20}m$
• D. $\frac{13}{40}m$

Answer 1

Answer: (A)

$\text{T}=\frac{{\text{2u sin 90}}^{\text{o}}}{{\text{g cos 30}}^o}=\frac{2\text{u}}{\text{g}\text{cos}30^{\text{o}}}$
$R=\frac{1}{2}\times \left(g\sin 30^{\circ }\right)\times \frac{4u^2}{g^2{\cos }^{2}30^{\circ }}$
$\text{R}=\frac{2{\text{u}}^2\times 4}{2\times 10\times 3}=\frac{2\times 10\times 10\times 4}{2\times 10\times 3}=\frac{40}{3}m$