A ball is moving without spinning in a straight line through a fluid (as shown) If pA and pB are pressure values at A and B, then

Question

A ball is moving without spinning in a straight line through a fluid (as shown) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/86557f0759f19f890c09da631c07b62c-.png" /> If pA and pB are pressure values at A and B, then (A) pA< pB (B) pB< pA (C) pA × pB=1 (D) pA / pB=1

Tardigrade Admin · Accepted Answer

As the ball is not spinning, then by Bernoulli's theorem, pA=pB. ⇒(pA / pB)=1

Q. A ball is moving without spinning in a straight line through a fluid (as shown)

If $p_{A}$ and $p_{B}$ are pressure values at $A$ and $B$ , then

$p_{A} < p_{B}$

$p_{B} < p_{A}$

$p_{A} \times p_{B} = 1$

$p_{A} / p_{B} = 1$

As the ball is not spinning, then by Bernoulli's theorem, $p_{A} = p_{B}$ .
$\Rightarrow (p_{A} / p_{B}) = 1$

Q. A ball is moving without spinning in a straight line through a fluid (as shown) If pA​ and pB​ are pressure values at A and B, then

pA​<pB​

pB​<pA​

pA​×pB​=1

pA​/pB​=1