A ball is dropped from the top of a building of height 80 m. At same instant another ball is thrown upwards with speed 50 m / s from the bottom of the building. The time at which balls will meet is

Question

A ball is dropped from the top of a building of height 80 m. At same instant another ball is thrown upwards with speed 50 m / s from the bottom of the building. The time at which balls will meet is (A) 1.6 s (B) 5 s (C) 8 s (D) 10 s

Tardigrade Admin · Accepted Answer

t=(h/v text rel )=(80/50) ⇒ t=1.6 s

Q. A ball is dropped from the top of a building of height $80 m$ . At same instant another ball is thrown upwards with speed $50 m / s$ from the bottom of the building. The time at which balls will meet is

1.6 s

5 s

8 s

10 s

$t = \frac{h}{v _{rel}} = \frac{80}{50}$
$\Rightarrow t = 1.6 s$

Q. A ball is dropped from the top of a building of height 80m. At same instant another ball is thrown upwards with speed 50m/s from the bottom of the building. The time at which balls will meet is

1.6 s

5 s

8 s

10 s

t=vrel ​h​=5080​ ⇒t=1.6s

Q. A ball is dropped from the top of a building of height $80 m$ . At same instant another ball is thrown upwards with speed $50 m / s$ from the bottom of the building. The time at which balls will meet is

$t = \frac{h}{v _{rel}} = \frac{80}{50}$
$\Rightarrow t = 1.6 s$