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Q. A ball is dropped from the top of a building of height $80\, m$. At same instant another ball is thrown upwards with speed $50\, m / s$ from the bottom of the building. The time at which balls will meet is

Motion in a Straight Line

Solution:

$t=\frac{h}{v_{\text {rel }}}=\frac{80}{50}$
$\Rightarrow t=1.6\, s$