A bag contains 5 white balls, 3 black balls, 4 yellow balls. A ball is drawn from the bag, its colour is noted and put back into the bag with 5 additional balls of the same colour. The process is repeated. The probability that a yellow ball is drawn in the 1s t draw given that a white ball is drawn in the 2n d draw is

Question

A bag contains 5 white balls, 3 black balls, 4 yellow balls. A ball is drawn from the bag, its colour is noted and put back into the bag with 5 additional balls of the same colour. The process is repeated. The probability that a yellow ball is drawn in the 1s t draw given that a white ball is drawn in the 2n d draw is (A) (9/55) (B) (4/17) (C) (1/5) (D) (2/11)

Tardigrade Admin · Accepted Answer

A= A yellow ball is drawn in the 1s t draw B= A white ball is drawn in the 2n d draw P((A/B))=(P (A ∩ B)/P (B))=((4/12) × (5/17)/(5)12 × (10)17 + (3/12) × (5/17) + (4/12) × (5/17) =(4/17)

$\frac{9}{55}$

$\frac{4}{17}$

$\frac{1}{5}$

$\frac{2}{11}$

559​

174​

51​

112​

A= A yellow ball is drawn in the 1st draw B= A white ball is drawn in the 2nd draw P(BA​)=P(B)P(A∩B)​=125​×1710​+123​×175​+124​×175​124​×175​​ =174​

$\frac{9}{55}$

$\frac{4}{17}$

$\frac{1}{5}$

$\frac{2}{11}$