A bag consists of 3 red balls, 5 blue balls, and 8 green balls. A ball is selected at random. What is the probability of not getting a blue ball?

Question

A bag consists of 3 red balls, 5 blue balls, and 8 green balls. A ball is selected at random. What is the probability of not getting a blue ball? (A) (11/6) (B) (3/16) (C) (1/2) (D) (5/16)

Tardigrade Admin · Accepted Answer

P(B)=(5/16) ⇒ P( barB)=(11/16)

Q. A bag consists of $3$ red balls, $5$ blue balls, and $8$ green balls. A ball is selected at random. What is the probability of not getting a blue ball?

$\frac{11}{6}$

$\frac{3}{16}$

$\frac{1}{2}$

$\frac{5}{16}$

$P (B) = \frac{5}{16}$
$\Rightarrow P (\overset{ˉ}{B}) = \frac{11}{16}$

Q. A bag consists of 3 red balls, 5 blue balls, and 8 green balls. A ball is selected at random. What is the probability of not getting a blue ball?

611​

163​

21​

165​