Q.
AB is a chord of a parabola y2=4ax,(a>0) with vertex A.BC is drawn perpendicular to AB meeting the axis at C. The projection of BC on the axis of the parabola is
B(at2,2at):D(at2,0) mAB=at22at=t2:mBC=−2t ∴y−2at=−2t(x−at2) [Equation of BC] for y=0,−2at=−2t(x−at2)=−2tx+2at3 ⇒tx=4at+at3 ⇒x=4a+at2 ∴c(4a+at2,0) ∴ Projection of BC on the axis is DC=AC−AD=4a+at2−at2=4a