Question

$\overrightarrow{a}+\overrightarrow{b}+\overrightarrow{c}=0$ and $|\overrightarrow{a}|=5,|\overrightarrow{b}|=4$ and $|\overrightarrow{c}|=3$ then the value of $|\overrightarrow{a}.\overrightarrow{b}+\overrightarrow{b}.\overrightarrow{c}+\overrightarrow{c}.\overrightarrow{a}|$ is

• A. 25
• B. 50
• C. -25
• D. 20

Answer 1

Answer: (C)

Given, $\vec{a}+\vec{b}+\vec{c}=\vec{0}$
$\therefore {\left|\vec{a}\right|}^2+{\left|\vec{b}\right|}^2+{\left|\vec{c}\right|}^2-2\vec{a}\cdot \vec{c}-2\vec{b}\cdot \vec{c}+2\vec{a}\cdot \vec{c}$
$=25+16+9+2\left[\vec{a}\cdot \vec{b}+\vec{b}\cdot \vec{c}-\vec{a}\cdot \vec{c}\right]=0$
$\Rightarrow 2\left[\vec{a}\cdot \vec{b}+\vec{b}\cdot \vec{c}-\vec{c}\cdot \vec{a}\right]=-50$
$\Rightarrow \left[\vec{a}\cdot \vec{b}+\vec{b}\cdot \vec{c}-\vec{c}\cdot \vec{a}\right]=-25$