Let the coordinates of B and C be (at12,2at1) and (at22,2at2) respectively.
Then, the coordinates of A are (at1t2,a(t1+t2)).
The equation of any tangent to y2=4ax is ty=x+at2. l1=1+t2at1t2−a(t1+t2)t+at2 l2=1+t2at12−2at1+at2
and l3=1+t2at22−2at2+at2
Clearly, l2l3=l12
Therefore, l2,l1,l3 are in GP.