A and B are two points on the axis and the perpendicular bisector respectively of an electric dipole. A and B are far away from the dipole and at equal distances from it. The potentials at A and B are VA and VB respectively. Then,

Question

A and B are two points on the axis and the perpendicular bisector respectively of an electric dipole. A and B are far away from the dipole and at equal distances from it. The potentials at A and B are VA and VB respectively. Then, (A) VA=VB=0 (B) VA=2 VB (C) VA ≠ 0, VB=0 (D) VA ≠ 0, VB ≠ 0

Tardigrade Admin · Accepted Answer

The potential at A and B are V A and V B respectively. If A and B are two points on the axis and the perpendicular bisector respectively of an electric dipole then V A ≠ 0 , V B = 0 because, for the perpendicularity cos θ will be 0 .

Q. $A$ and $B$ are two points on the axis and the perpendicular bisector respectively of an electric dipole. $A$ and $B$ are far away from the dipole and at equal distances from it. The potentials at $A$ and $B$ are $V_{A}$ and $V_{B}$ respectively. Then,

$V_{A} = V_{B} = 0$

$V_{A} = 2 V_{B}$

$V_{A} \neq = 0, V_{B} = 0$

$V_{A} \neq = 0, V_{B} \neq = 0$

The potential at $A$ and $B$ are $V_{A}$ and $V_{B}$ respectively.
If $A$ and $B$ are two points on the axis and the perpendicular bisector respectively of an electric dipole
then $V_{A} \neq = 0, V_{B} = 0$
because, for the perpendicularity $cos θ$ will be $0.$

Q. A and B are two points on the axis and the perpendicular bisector respectively of an electric dipole. A and B are far away from the dipole and at equal distances from it. The potentials at A and B are VA​ and VB​ respectively. Then,

VA​=VB​=0

VA​=2VB​

VA​=0,VB​=0

VA​=0,VB​=0