A and B are two parallel sided transparent slabs of refractive indices n1 and n2 respectively. A ray is incident at an angle θ on the surface of separation of A and B, and after refraction from B into air grazes the surface of B. Then

Question

A and B are two parallel sided transparent slabs of refractive indices n1 and n2 respectively. A ray is incident at an angle θ on the surface of separation of A and B, and after refraction from B into air grazes the surface of B. Then (A) sin θ =(1/n2) (B) sin θ =(1/n1) (C) sin θ =(n2/n1) (D) sin θ =(n1/n2)

Tardigrade Admin · Accepted Answer

From snellâs law n1 sin θ =1 sin θ =(1/n1)

Q. A and B are two parallel sided transparent slabs of refractive indices n $_{1}$ and n $_{2}$ respectively. A ray is incident at an angle $θ$ on the surface of separation of A and B, and after refraction from B into air grazes the surface of B. Then

$s in θ = \frac{1}{n ^{2}}$

$s in θ = \frac{1}{n _{1}}$

$s in θ = \frac{n _{2}}{n _{1}}$

$s in θ = \frac{n _{1}}{n _{2}}$

From snell’s law
$n_{1} s in θ = 1$
$s in θ = \frac{1}{n _{1}}$

Q. A and B are two parallel sided transparent slabs of refractive indices n1​and n2​ respectively. A ray is incident at an angle θ on the surface of separation of A and B, and after refraction from B into air grazes the surface of B. Then

sinθ=n21​

sinθ=n1​1​

sinθ=n1​n2​​

sinθ=n2​n1​​