A and B are two like parallel forces. A couple of moment H lies in the plane of A and B and is contained with them. The resultant of A and B after combining is displaced through a distance :

Question

A and B are two like parallel forces. A couple of moment H lies in the plane of A and B and is contained with them. The resultant of A and B after combining is displaced through a distance : (A) (H/A-B) (B) (H/2(A+B)) (C) (H/A+B) (D) (2H/A-B)

Tardigrade Admin · Accepted Answer

Let the resultant of A and B is displaced by x. Then change in net momentum of A and B = applied momentum ∴ Ax + Bx =H ⇒ x = (H/A+B)

Q. $A$ and $B$ are two like parallel forces. A couple of moment $H$ lies in the plane of $A$ and $B$ and is contained with them. The resultant of $A$ and $B$ after combining is displaced through a distance :

$\frac{H}{A - B}$

$\frac{H}{2 ( A + B )}$

$\frac{H}{A + B}$

$\frac{2 H}{A - B}$

Let the resultant of A and B is displaced by x. Then change in net momentum of A and B = applied momentum
$∴ A x + B x = H$
$\Rightarrow x = \frac{H}{A + B}$

Q. A andB are two like parallel forces. A couple of moment H lies in the plane of A and B and is contained with them. The resultant of A and B after combining is displaced through a distance :

A−BH​

2(A+B)H​

A+BH​

A−B2H​