A and B are two identical vessels. A contains 15 g of ethane at 298 K and 1 atm. The vessel B contains 75 g gas X2 at the same temperature and pressure. The vapour density of X2 is :

Question

A and B are two identical vessels. A contains 15 g of ethane at 298 K and 1 atm. The vessel B contains 75 g gas X2 at the same temperature and pressure. The vapour density of X2 is : (A) 75 (B) 150 (C) 37.5 (D) 300

Tardigrade Admin · Accepted Answer

P 1 V 1=( w 1/30) RT 1 ; ( w 1=15) P 2 V 2=( w 2/ M ) RT 2 ; ( w 2=75) If P 1= P 2, V 1= V 2, T 1= T 2, Then M =150, also V.D. = M / 2= (150/2)=75

Q. $A$ and $B$ are two identical vessels. $A$ contains $15 g$ of ethane at $298 K$ and $1$ atm. The vessel $B$ contains $75 g$ gas $X_{2}$ at the same temperature and pressure. The vapour density of $X_{2}$ is :

75

150

37.5

300

$P_{1} V_{1} = \frac{w _{1}}{30} R T_{1}; (w_{1} = 15)$
$P_{2} V_{2} = \frac{w _{2}}{M} R T_{2}; (w_{2} = 75)$
If $P_{1} = P_{2}, V_{1} = V_{2}, T_{1} = T_{2}$ ,
Then $M = 150$ , also V.D. $= M /2 =$
$\frac{150}{2} = 75$

Q. A and B are two identical vessels. A contains 15g of ethane at 298K and 1 atm. The vessel B contains 75g gas X2​ at the same temperature and pressure. The vapour density of X2​ is :

75

150

37.5

300

P1​V1​=30w1​​RT1​;(w1​=15) P2​V2​=Mw2​​RT2​;(w2​=75) If P1​=P2​,V1​=V2​,T1​=T2​, Then M=150, also V.D. =M/2= 2150​=75

Q. $A$ and $B$ are two identical vessels. $A$ contains $15 g$ of ethane at $298 K$ and $1$ atm. The vessel $B$ contains $75 g$ gas $X_{2}$ at the same temperature and pressure. The vapour density of $X_{2}$ is :

$P_{1} V_{1} = \frac{w _{1}}{30} R T_{1}; (w_{1} = 15)$
$P_{2} V_{2} = \frac{w _{2}}{M} R T_{2}; (w_{2} = 75)$
If $P_{1} = P_{2}, V_{1} = V_{2}, T_{1} = T_{2}$ ,
Then $M = 150$ , also V.D. $= M /2 =$
$\frac{150}{2} = 75$