Tardigrade
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Tardigrade
Question
Mathematics
A and B are events such that P(A ∪ B)=3/ 4, P (A ∩ B)=1 /4, P ( barA)= 2 /3 if P ( barA ∩ B) is =(a/b), then a × b is
Q.
A
and
B
are events such that
P
(
A
∪
B
)
=
3/4
,
P
(
A
∩
B
)
=
1/4
,
P
(
A
ˉ
)
=
2/3
if
P
(
A
ˉ
∩
B
)
is
=
b
a
, then
a
×
b
is
1823
194
Probability
Report Error
Answer:
60
Solution:
P
(
A
∪
B
)
=
P
(
A
)
+
P
(
B
)
−
P
(
A
∩
B
)
;
⇒
4
3
=
1
−
P
(
A
ˉ
)
+
P
(
B
)
−
4
1
⇒
1
=
1
−
3
2
+
P
(
B
)
⇒
P
(
B
)
=
3
2
;
Now,
P
(
A
ˉ
∩
B
)
=
P
(
B
)
−
P
(
A
∩
B
)
=
3
2
−
4
1
=
12
5
⇒
12
5
=
b
a
⇒
a
=
5
,
b
=
12
∴
a
×
b
=
5
×
12
=
60