Q.
A90cm long solenoid has six layers of windings of 450 turns each. If the diameter of solenoid is 2.2cm and current carried is 6A , then the magnitude of magnetic field inside the solenoid, near its centre is
For six layers of windings the total number of turns = 6×450=2700
Now number of turns per unit length n=lN=90×10−22700=3000
Then the field inside the solenoid near the centre B=μ0nI=4π×10−7×3000×6 =72π×10−4T =72πG