A 80 μ F capacitor in a defibrillator is charged to 1000 V The energy stored in the capacitor is sent through the patient during a pulse of duration 3 ms. The power delivered to the patient is

Question

A 80 μ F capacitor in a defibrillator is charged to 1000 V The energy stored in the capacitor is sent through the patient during a pulse of duration 3 ms. The power delivered to the patient is (A) 13.3 kW (B) 14.5 kW (C) 15 kW (D) 9 kW

Tardigrade Admin · Accepted Answer

P =( W / t ) ⇒ P =(1/2) ( CV 2/ t ) P=(80 × 10-6 × 106/2 × 3 × 10-3) =13.3 × 103 watt P=13.3 kW

Q. A $80 μ F$ capacitor in a defibrillator is charged to $1000 V$ The energy stored in the capacitor is sent through the patient during a pulse of duration $3 m s$ . The power delivered to the patient is

$13.3 kW$

$14.5 kW$

$15 kW$

$9 kW$

$P = \frac{W}{t}$
$\Rightarrow P = \frac{1}{2} \frac{C V ^{2}}{t}$
$P = \frac{80 \times 1 0 ^{- 6} \times 1 0 ^{6}}{2 \times 3 \times 1 0 ^{- 3}}$
$= 13.3 \times 1 0^{3}$ watt
$P = 13.3 kW$

Q. A 80μF capacitor in a defibrillator is charged to 1000V The energy stored in the capacitor is sent through the patient during a pulse of duration 3ms. The power delivered to the patient is

13.3kW

14.5kW

15kW

9kW