Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A $80 \mu F$ capacitor in a defibrillator is charged to $1000 \,V$ The energy stored in the capacitor is sent through the patient during a pulse of duration $3 ms$. The power delivered to the patient is

Electrostatic Potential and Capacitance

Solution:

$P =\frac{ W }{ t }$
$ \Rightarrow P =\frac{1}{2} \frac{ CV ^{2}}{ t }$
$P=\frac{80 \times 10^{-6} \times 10^{6}}{2 \times 3 \times 10^{-3}}$
$=13.3 \times 10^{3}$ watt
$P=13.3 \,kW$