A 700 g solid cube having an edge of length 10 cm floats in water. The volume of cube outside water is :

Question

A 700 g solid cube having an edge of length 10 cm floats in water. The volume of cube outside water is : (A) 24 cm3 (B) 4.8 cm3 (C) 300 cm3 (D) 500 cm3

Tardigrade Admin · Accepted Answer

If V be the volume of the cube inside the water then, V× 1000× 10=0.7× 10 V=(7/10000)=700 cm3 Total volume of the cube =(10 text cm)3 =1000 text cm3 Volume outside the water =1000-700 =300 text cm3

Q. A 700 g solid cube having an edge of length 10 cm floats in water. The volume of cube outside water is :

24 cm3

4.8 cm3

300 cm3

500 cm3

If V be the volume of the cube inside the water then, $V \times 1000 \times 10 = 0.7 \times 10$ $V = \frac{7}{10000} = 700 c m^{3}$ Total volume of the cube $= (10 c m)^{3}$ $= 1000 c m^{3}$ Volume outside the water $= 1000 - 700$ $= 300 c m^{3}$

Q. A 700 g solid cube having an edge of length 10 cm floats in water. The volume of cube outside water is :

24 cm3

4.8 cm3

300 cm3

500 cm3

If V be the volume of the cube inside the water then, V×1000×10=0.7×10 V=100007​=700cm3 Total volume of the cube =(10cm)3 =1000cm3 Volume outside the water =1000−700 =300cm3

If V be the volume of the cube inside the water then, $V \times 1000 \times 10 = 0.7 \times 10$ $V = \frac{7}{10000} = 700 c m^{3}$ Total volume of the cube $= (10 c m)^{3}$ $= 1000 c m^{3}$ Volume outside the water $= 1000 - 700$ $= 300 c m^{3}$