A 60 μ F capacitor is connected to a 110 V (rms), 60 Hz ac supply, the net power absorbed by the circuit in one complete cycle is

Question

A 60 μ F capacitor is connected to a 110 V (rms), 60 Hz ac supply, the net power absorbed by the circuit in one complete cycle is (A) 5 W (B) 10 W (C) 15 W (D) zero

Tardigrade Admin · Accepted Answer

As P=Vrms Irms Irms cos φ In a pure capacitance circuit, the phase difference between alternating voltage and current is π /2. Hence P = Vrms Irms cos 90° = 0.

Q. A $60 μ F$ capacitor is connected to a $110 V (r m s)$ , $60 Hz$ ac supply, the net power absorbed by the circuit in one complete cycle is

$5 W$

$10 W$

$15 W$

zero

As $P = V_{r m s} I_{r m s} I_{r m s} cos ϕ$
In a pure capacitance circuit, the phase difference between alternating voltage and current is $π /2$ . Hence
$P = V_{r m s} I_{r m s} cos 9 0^{°} = 0$ .

Q. A 60μF capacitor is connected to a 110V(rms), 60Hz ac supply, the net power absorbed by the circuit in one complete cycle is

5W

10W

15W