Thank you for reporting, we will resolve it shortly
Q.
A $60\,\mu F$ capacitor is connected to a $110\,V (rms)$, $60\,Hz$ ac supply, the net power absorbed by the circuit in one complete cycle is
Alternating Current
Solution:
As $P=V_{rms}\,I_{rms}\,I_{rms}\,cos\,\phi$
In a pure capacitance circuit, the phase difference between alternating voltage and current is $\pi /2$. Hence
$P = V_{rms}\,I_{rms}\,cos\,90^° = 0$.