Q.
A 60kg man stands on a spring scale in the lift. At some instant he finds, scale reading has changed from 60kg to 50kg for a while and then comes back to the original mark. What should we conclude?
For upward acceleration apparent weight =m(g+a)
If lift suddenly stops during upward motion then apparent weight =m(g−a) because instead of acceleration, we will consider retardation.
In the problem it is given that scale reading initially was 60kg and due to sudden jerk reading decreases and finally comes back to the original mark ie, 60kg.
So, we can conclude that lift was moving upwards with constant speed and suddenly stops.