A 6 kg bomb at rest explodes into three equal pieces P, Q and R. If P flies with speed 30 m / s and Q with speed 40 m / s making an angle 90° with the direction of P. The angle between the direction of motion of P. and R is about

Question

A 6 kg bomb at rest explodes into three equal pieces P, Q and R. If P flies with speed 30 m / s and Q with speed 40 m / s making an angle 90° with the direction of P. The angle between the direction of motion of P. and R is about (A) 143° (B) 127° (C) 120° (D) 150°

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/311849d8766f9bcf2a554dd0f069fdf6-.png" /> PP=30(2)=60 kg ms -1 PQ=40(2)=80 kg ms -1 tan θ=(60/80)=3 / 4 θ=37° So angle between P and R will be 90°+37°=127°

Q. A $6 k g$ bomb at rest explodes into three equal pieces $P, Q$ and $R$ . If $P$ flies with speed $30 m / s$ and $Q$ with speed $40 m / s$ making an angle $9 0^{\circ}$ with the direction of $P$ . The angle between the direction of motion of $P$ . and $R$ is about

$14 3^{\circ}$

$12 7^{\circ}$

$12 0^{\circ}$

$15 0^{\circ}$

$P_{P} = 30 (2) = 60 k g m s^{- 1}$
$P_{Q} = 40 (2) = 80 k g m s^{- 1}$
$tan θ = \frac{60}{80} = 3/4$
$θ = 3 7^{\circ}$
So angle between $P$ and $R$ will be
$9 0^{\circ} + 3 7^{\circ} = 12 7^{\circ}$

Q. A 6kg bomb at rest explodes into three equal pieces P,Q and R. If P flies with speed 30m/s and Q with speed 40m/s making an angle 90∘ with the direction of P. The angle between the direction of motion of P. and R is about

143∘

127∘

120∘

150∘