Question

A $6.0$ volt battery is connected to two light bulbs as shown in figure. Light bulb $1$ has resistance $3$ ohm while light bulb $2$ has resistance $6$ ohm. Battery has negligible internal resistance. Which bulb will glow brighter?

• A. Bulb 1 will glow more first and then its brightness will become less than bulb 2
• B. Bulb 1
• C. Bulb 2
• D. Both glow equally

Answer 1

Answer: (B)

Total resistance $=\frac{6\times 3}{6+3}=2\Omega$
Current in circuit $=\frac{6}{2}=3A$
Therefore current through bulb 1 is $2A$ and bulb 2 is $1A$. So bulb 1 will glow more