A 500 Ω resistor and a capacitor C are connected in series across 50 Hz AC supply mains. The r.m.s. potential difference recorded on voltmeter V1 and V2 are V1=120 V and V2=160 V. The power taken from the mains is

Question

A 500 Ω resistor and a capacitor C are connected in series across 50 Hz AC supply mains. The r.m.s. potential difference recorded on voltmeter V1 and V2 are V1=120 V and V2=160 V. The power taken from the mains is (A) 480 W (B) 240 W (C) 28.8 W (D) 14.4 W

Tardigrade Admin · Accepted Answer

IV × 500=120,IV=0.24 A P=IV2 R=(0.24)2 × 500=28.8 W

Q. A $500 Ω$ resistor and a capacitor $C$ are connected in series across $50 Hz$ AC supply mains. The r.m.s. potential difference recorded on voltmeter $V_{1}$ and $V_{2}$ are $V_{1} = 120 V$ and $V_{2} = 160 V$ . The power taken from the mains is

480 W

240 W

28.8 W

14.4 W

$I_{V} \times 500 = 120, I_{V} = 0.24 A$
$P = I_{V}^{2} R = (0.24)^{2} \times 500 = 28.8 W$

Q. A 500Ω resistor and a capacitor C are connected in series across 50Hz AC supply mains. The r.m.s. potential difference recorded on voltmeter V1​ and V2​ are V1​=120V and V2​=160V. The power taken from the mains is