A 500 μ F capacitor is charged at a rate of 125 μ C / sec. The potential difference across the capacitor will be 10 V after an interval of

Question

A 500 μ F capacitor is charged at a rate of 125 μ C / sec. The potential difference across the capacitor will be 10 V after an interval of (A) 80 sec (B) 50 sec (C) 20 sec (D) 40 sec

Tardigrade Admin · Accepted Answer

Q=C V ⇒ Q=500 × 10-6 × 10=5000 × 10-6 C The time interval required to charge the capacitor to 5000 × 10-6 C will be equal to the one required for producing potential difference of 10 V. T =( text Total charge / text Rate of charging ) =(5000 × 10-6/125 × 10-6) =40 sec

Q. A $500 μ F$ capacitor is charged at a rate of $125 μ C / sec$ . The potential difference across the capacitor will be $10 V$ after an interval of

$80 sec$

$50 sec$

$20 sec$

$40 sec$

Q. A 500μF capacitor is charged at a rate of 125μC/sec. The potential difference across the capacitor will be 10V after an interval of

80sec

50sec

20sec

40sec

Q=CV ⇒Q=500×10−6×10=5000×10−6C The time interval required to charge the capacitor to 5000×10−6C will be equal to the one required for producing potential difference of 10V. T= Rate of charging Total charge ​ =125×10−65000×10−6​ =40sec

Q. A $500 μ F$ capacitor is charged at a rate of $125 μ C / sec$ . The potential difference across the capacitor will be $10 V$ after an interval of

$80 sec$

$50 sec$

$20 sec$

$40 sec$