Q.
A 500kg car, moving with a velocity of 36kmh−1 on a straight road undirectionally, doubles its velocity in one minute. The power delivered by the engine for doubling the velocity is
u=10ms−1,v=20ms−1
According to work-energy theorem
Work done = change in kinetic energy =21mv2−21mu2 =21×500[202−102] =2500×30×10
The power delivered by the engine is P=2×60500×30×10W=1250W