Q.
A 500kg boat is 9m long and is floating without motion on still water. A man of mass 100kg is at one end and if he runs to the other end of the boat and stops, the displacement of the boat is
Given that the system is initially at rest,
i. e. , vCM=0 ∴m1+m2m1v1+m2v2=0 m1v1+m2v2=0 m1ΔtΔr1+m2Δ,tΔr2=0 m1Δr1+m2r2=0
Now here, in boat-man system, if the man moves towards right the boat moves toward left m1Δr1±m2Δr2
If Δr2 is the displacement of boat relative to shore; there the displacement of man relative to shore would be (9−Δr2) Δr1=9−Δr2 m1(9−Δr2)=m2Δr2 100(9−Δr2)=500Δr2 Δr2=600100×9=1.5m
i. e. , Boat moves 1.5m relative to shore in the direction opposite to the displacement of man.