Question

A $50mH$ coil carries a current of $2A$ , the energy stored in joule is:

• A. 1
• B. 0.05
• C. 10
• D. 0.5
• E. 0.1

Answer 1

Answer: (E)

$U=\frac{1}{2}L{i}^2=\frac{1}{2}\times 50\times {10}^{-3}\times 2\times 2=0.1J$