A 5 molar solution of H2SO4 is diluted from 1 litre to a volume of 10 litres, the normality of the solution will be

Question

A 5 molar solution of H2SO4 is diluted from 1 litre to a volume of 10 litres, the normality of the solution will be (A) 1 N (B) 0.1 N (C) 5 N (D) 0.5 N

Tardigrade Admin · Accepted Answer

N 1 V 1= N 2 V 2 Given, molarity of H 2 SO 4=5 M, N 1= Molarity × basicity =5 × 2=10 V 1=1 L, V 2=10 L, N 2=? N 1 V 1= N 2 V 2 10 × 1= N 2 × 10 ∴ N 2=1 N

Q. A $5$ molar solution of $H_{2} S O_{4}$ is diluted from 1 litre to a volume of 10 litres, the normality of the solution will be

1 N

0.1 N

5 N

0.5 N

$N_{1} V_{1} = N_{2} V_{2}$
Given, molarity of $H_{2} S O_{4} = 5 M$ ,
$N_{1} =$ Molarity $\times$ basicity $= 5 \times 2 = 10$
$V_{1} = 1 L, V_{2} = 10 L, N_{2} = ?$
$N_{1} V_{1} = N_{2} V_{2}$
$10 \times 1 = N_{2} \times 10$
$∴ N_{2} = 1 N$

Q. A 5 molar solution of H2​SO4​ is diluted from 1 litre to a volume of 10 litres, the normality of the solution will be

1 N

0.1 N

5 N

0.5 N

N1​V1​=N2​V2​ Given, molarity of H2​SO4​=5M, N1​= Molarity × basicity =5×2=10 V1​=1L,V2​=10L,N2​=? N1​V1​=N2​V2​ 10×1=N2​×10 ∴N2​=1N

Q. A $5$ molar solution of $H_{2} S O_{4}$ is diluted from 1 litre to a volume of 10 litres, the normality of the solution will be

$N_{1} V_{1} = N_{2} V_{2}$
Given, molarity of $H_{2} S O_{4} = 5 M$ ,
$N_{1} =$ Molarity $\times$ basicity $= 5 \times 2 = 10$
$V_{1} = 1 L, V_{2} = 10 L, N_{2} = ?$
$N_{1} V_{1} = N_{2} V_{2}$
$10 \times 1 = N_{2} \times 10$
$∴ N_{2} = 1 N$