A 5 kg collar is attached to a spring of spring constant 500 N m-1. It slides without friction over a horizontal rod. The collar is displaced from its equilibrium position by 10 cm and released. The time period of oscillation is

Question

A 5 kg collar is attached to a spring of spring constant 500 N m-1. It slides without friction over a horizontal rod. The collar is displaced from its equilibrium position by 10 cm and released. The time period of oscillation is (A) (π/5) s (B) (π/2) s (C) π s (D) 2 π s

Tardigrade Admin · Accepted Answer

Here, m = 5 kg, k = 500 N m- 1, A = 10 cm = 0.1 m Time period of oscillation is T = 2π√(m/k) = 2π√(5 kg/500 N m-1) = (2π/10) s = (π/5) s

Q. A $5 k g$ collar is attached to a spring of spring constant $500 N m^{- 1}$ . It slides without friction over a horizontal rod. The collar is displaced from its equilibrium position by $10 c m$ and released. The time period of oscillation is

$\frac{π}{5} s$

$\frac{π}{2} s$

$π s$

$2 π s$

Here, $m = 5 k g, k = 500 N m^{- 1}, A = 10 c m = 0.1 m$
Time period of oscillation is
$T = 2 π \frac{m}{k}$
$= 2 π \frac{5 k g}{500 N m ^{- 1}}$
$= \frac{2 π}{10} s$
$= \frac{π}{5} s$

Q. A 5kg collar is attached to a spring of spring constant 500Nm−1. It slides without friction over a horizontal rod. The collar is displaced from its equilibrium position by 10cm and released. The time period of oscillation is

5π​s

2π​s

πs

2πs