A 5° C rise in temperature is observed in a conductor by passing a current. When the current is doubled the rise in temperature will be approximately

Question

A 5° C rise in temperature is observed in a conductor by passing a current. When the current is doubled the rise in temperature will be approximately (A) 5°C (B) 20°C (C) 15°C (D) 25°C

Tardigrade Admin · Accepted Answer

H=I2 R t=m s Δ T (I12/I22)=(Δ T1/Δ T2) or, Δ T2=(Δ T1 I22/I12) Δ T2=5 × ((2 I1)2/I12)=20 ; Δ T2=20° C .

Q. A $5^{\circ} C$ rise in temperature is observed in a conductor by passing a current. When the current is doubled the rise in temperature will be approximately

$5^{\circ} C$

$2 0^{\circ} C$

$1 5^{\circ} C$

$2 5^{\circ} C$

$H = I^{2} Rt = m s Δ T$
$\frac{I _{1}^{2}}{I _{2}^{2}} = \frac{Δ T _{1}}{Δ T _{2}}$
or, $Δ T_{2} = \frac{Δ T _{1} I _{2}^{2}}{I _{1}^{2}}$
$Δ T_{2} = 5 \times \frac{( 2 I _{1} ) ^{2}}{I _{1}^{2}} = 20;$
$Δ T_{2} = 2 0^{\circ} C .$

Q. A 5∘C rise in temperature is observed in a conductor by passing a current. When the current is doubled the rise in temperature will be approximately

5∘C

20∘C

15∘C

25∘C