Question

A $5.0$ amp current is setup in an external circuit by a $6.0$ volt storage battery for $6.0$ minutes. The chemical energy of the battery is reduced by

• A. $1.08\times 10^{4}J$
• B. $1.08\times 10^{4}J$
• C. $1.8\times 10^{4}J$
• D. $1.8\times 10^4$ volt

Answer 1

Answer: (A)

Given: $V=6.0$ volts $I=5.0A$
Time for which current flows, $t=6\times 60=360s$
Electric power spent by the battery $P=VI$
$\Rightarrow P=6\times 5=30W$ or $30J/s$
Electric energy spent by the battery $E=P$ ower $\times$ time
$<br/>\therefore E=30J/s\times 360s=1.08\times 10^{4}J<br/>$
This electric energy came from the chemical energy stored within the battery. So the energy of the battery is reduced by $1.08\times 10^{4}J$.