Question

A $40\mu F$ capacitor is connected to a $200V$,$50Hz$ ac supply. The rms value of the current in the circuit is, nearly :

• A. 1. 7 A
• B. 2. 05 A
• C. 2. 5 A
• D. 25. 1 A

Answer 1

Answer: (C)

The rms value of the current
$i_{\text{rms}}=C\omega {\epsilon }_{\text{rms}}$
$C=40\times 10^{-6}F$
$\omega =2\pi f=100\pi$
${\epsilon }_{\text{rms}}=200V$
$\therefore i_{\text{rms}}=200\times 40\times 10^{-6}\times 2\pi \times 50$
$=2.5A$