A 40 μ F capacitor in a defibrillator is charged to 3000 V . The energy stored in the capacitor is sent through the patient during a pulse of duration 2 ms . The power delivered to the patient is

Question

A 40 μ F capacitor in a defibrillator is charged to 3000 V . The energy stored in the capacitor is sent through the patient during a pulse of duration 2 ms . The power delivered to the patient is (A) 45 kW (B) 90 kW (C) 180 kW (D) 360 kW

Tardigrade Admin · Accepted Answer

Power, P=(E n e r g y/t i m e)=((1/2) C V2/t) P=(C V2/2 t) P=(40 × 1 6- 6 × 9 × 1 06/2 × 2 × 1 0- 3) P=90× 1000 P=90 kW

Q. A $40 μ F$ capacitor in a defibrillator is charged to $3000 V$ . The energy stored in the capacitor is sent through the patient during a pulse of duration $2 m s$ . The power delivered to the patient is

$45 kW$

$90 kW$

$180 kW$

$360 kW$

Power, $P = \frac{E n er g y}{t im e} = \frac{\frac{1}{2} C V ^{2}}{t}$
$P = \frac{C V ^{2}}{2 t}$
$P = \frac{40 \times 1 6 ^{- 6} \times 9 \times 1 0 ^{6}}{2 \times 2 \times 1 0 ^{- 3}}$
$P = 90 \times 1000$
$P = 90 kW$

Q. A 40μF capacitor in a defibrillator is charged to 3000V . The energy stored in the capacitor is sent through the patient during a pulse of duration 2ms . The power delivered to the patient is

45kW

90kW

180kW

360kW