A 3d-electron having spin quantum number, s=+(1/2), can have a magnetic quantum number:

Question

A 3d-electron having spin quantum number, s=+(1/2), can have a magnetic quantum number: (A) 3 (B) -2 (C) 4 (D) -3

Tardigrade Admin · Accepted Answer

For d-sub-shell, the value of azimuthal quantum number (l)=2. ∴ Total number of values of m=(2l+1)=5 These five values of m are -2, -1, 0, +1 and +2. Hence, 3d-electron can have -2 magnetic quantum number. (-3 and +3 values are possible only for f-orbitals)

Q. A 3d-electron having spin quantum number, $s = + \frac{1}{2},$ can have a magnetic quantum number:

3

-2

4

-3

For d-sub-shell, the value of azimuthal quantum number $(l) = 2.$ $∴$ Total number of values of $m = (2 l + 1) = 5$ These five values of m are -2, -1, 0, +1 and +2. Hence, 3d-electron can have -2 magnetic quantum number. (-3 and +3 values are possible only for f-orbitals)

Q. A 3d-electron having spin quantum number, s=+21​, can have a magnetic quantum number:

3

-2

4

-3

For d-sub-shell, the value of azimuthal quantum number (l)=2. ∴ Total number of values of m=(2l+1)=5 These five values of m are -2, -1, 0, +1 and +2. Hence, 3d-electron can have -2 magnetic quantum number. (-3 and +3 values are possible only for f-orbitals)

Q. A 3d-electron having spin quantum number, $s = + \frac{1}{2},$ can have a magnetic quantum number:

For d-sub-shell, the value of azimuthal quantum number $(l) = 2.$ $∴$ Total number of values of $m = (2 l + 1) = 5$ These five values of m are -2, -1, 0, +1 and +2. Hence, 3d-electron can have -2 magnetic quantum number. (-3 and +3 values are possible only for f-orbitals)