A2B dissociates as A2B(s) leftharpoons􏰇􏰇􏰇 2A(g) + B(g). At equilibrium total pressure is P, then Kp of the reaction is

Question

A2B dissociates as A2B(s) leftharpoons􏰇􏰇􏰇 2A(g) + B(g). At equilibrium total pressure is P, then Kp of the reaction is (A)  (2/9)P2 (B)  (2/9)P3 (C)  (4/27)P3 (D) 4P3

Tardigrade Admin · Accepted Answer

A2B(s) leftharpoonsô°ô°ô° 2A(g) + B(g) 2:1 (2/3)P (P/3) ∴ Kp=((2/3)P)2((P/3))=(4/27)P3

Q. $A_{2} B$ dissociates as $A_{2} B (s)$ $⇌$ 􏰇􏰇􏰇 2A(g) + B(g). At equilibrium total pressure is P, then $K_{p}$ of the reaction is

$\frac{2}{9} P^{2}$

$\frac{2}{9} P^{3}$

$\frac{4}{27} P^{3}$

$4 P^{3}$

$A_{2} B (s) ⇌ 􏰇􏰇􏰇2 A (g) + B (g)$
$2 : 1$
$\frac{2}{3} P \frac{P}{3}$
$∴ K_{p} = (\frac{2}{3} P)^{2} (\frac{P}{3}) = \frac{4}{27} P^{3}$

Q. A2​B dissociates as A2​B(s) ⇌􏰇􏰇􏰇 2A(g) + B(g). At equilibrium total pressure is P, then Kp​ of the reaction is

92​P2

92​P3

274​P3

4P3