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  3. Chemistry
  4. A2B dissociates as A2B(s) leftharpoons􏰇􏰇􏰇 2A(g) + B(g). At equilibrium total pressure is P, then Kp of the reaction is

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Q. $A_2B$ dissociates as $A_2B(s)$ $\rightleftharpoons$􏰇􏰇􏰇 2A(g) + B(g). At equilibrium total pressure is P, then $K_p$ of the reaction is

Solution:

$A_2B(s) \rightleftharpoons􏰇􏰇􏰇 2A(g) + B(g)$
$2:1$
$\frac{2}{3}P\,\,\, \frac{P}{3} $
$\therefore K_{p}=\left(\frac{2}{3}P\right)^{2}\left(\frac{P}{3}\right)=\frac{4}{27}P^{3}$