A 220 - volt input is supplied to a Transformer. The output circuit draws a current of 2.0 ampere at 440 volts. If the efficiency of the transformer is 80 %, the current drawn by the primary windings of the transformer is :-

Question

A 220 - volt input is supplied to a Transformer. The output circuit draws a current of 2.0 ampere at 440 volts. If the efficiency of the transformer is 80 %, the current drawn by the primary windings of the transformer is :- (A) 5.0 ampere (B) 3.6 ampere (C) 2.8 ampere (D) 2.5 ampere

Tardigrade Admin · Accepted Answer

η=( V S I S / V P I P )=0.8 ⇒ I P =((440)(2)/(0.8)(220))=5 A

Q. A $220$ - volt input is supplied to a Transformer. The output circuit draws a current of $2.0$ ampere at $440$ volts. If the efficiency of the transformer is $80%$ , the current drawn by the primary windings of the transformer is :-

5.0 ampere

3.6 ampere

2.8 ampere

2.5 ampere

$η = \frac{V _{S} I _{S}}{V _{P} I _{P}} = 0.8$
$\Rightarrow I_{P} = \frac{( 440 ) ( 2 )}{( 0.8 ) ( 220 )} = 5 A$

Q. A 220 - volt input is supplied to a Transformer. The output circuit draws a current of 2.0 ampere at 440 volts. If the efficiency of the transformer is 80%, the current drawn by the primary windings of the transformer is :-