A 20 μ F capacitor is connected to 45 V battery through a circuit whose resistance is 2000 Ω . What is the final charge on the capacitor?

Question

A 20 μ F capacitor is connected to 45 V battery through a circuit whose resistance is 2000 Ω . What is the final charge on the capacitor? (A)  9 × 10-4 C  (B)  9.154 × 10-4 C  (C)  9.8 × 10-4 C  (D) None of these

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/d0a2b4d1315f0ff07024bf1d5f5257bf-.png" /> We know that in steady state the capacitor behaves like as an open circuit i.e., capacitor will not pass the current. So, the potential difference across the capacitor = 45 V Hence, the final charge on the capacitor is q=cv Here, C =20 μ F, V=45 V ∴ q=20×10-6×45 or q=900×10-6 or q=9×10-4 C

Q. A $20 μ F$ capacitor is connected to $45 V$ battery through a circuit whose resistance is $2000 Ω$ . What is the final charge on the capacitor?

$9 \times 1 0^{- 4} C$

$9.154 \times 1 0^{- 4} C$

$9.8 \times 1 0^{- 4} C$

None of these

Q. A 20μF capacitor is connected to 45V battery through a circuit whose resistance is 2000Ω . What is the final charge on the capacitor?

9×10−4C

9.154×10−4C

9.8×10−4C

None of these

We know that in steady state the capacitor behaves like as an open circuit i.e., capacitor will not pass the current. So, the potential difference across the capacitor =45V Hence, the final charge on the capacitor is q=cv Here, C=20μF,V=45V ∴q=20×10−6×45 or q=900×10−6 or q=9×10−4C

Q. A $20 μ F$ capacitor is connected to $45 V$ battery through a circuit whose resistance is $2000 Ω$ . What is the final charge on the capacitor?

$9 \times 1 0^{- 4} C$

$9.154 \times 1 0^{- 4} C$

$9.8 \times 1 0^{- 4} C$