A 15 pF capacitor is connected to a 60 V battery. How much electrostatic energy is stored?

Question

A 15 pF capacitor is connected to a 60 V battery. How much electrostatic energy is stored? (A)  2.77× 10-8 J  (B)  1.77× 10-8 J  (C)  2.35× 10-8 J  (D)  1.35× 10-8 J

Tardigrade Admin · Accepted Answer

Electrostatic energy U=(1/2) C V2 =(1/2)(15 × 10-12) ×(60)2 =(1/2) × 15 × 36 × 10-12 × 102 =270 × 10-10 =2.70 × 10-8 J

Q. A $15 pF$ capacitor is connected to a $60 V$ battery. How much electrostatic energy is stored?

$2.77 \times 1 0^{- 8} J$

$1.77 \times 1 0^{- 8} J$

$2.35 \times 1 0^{- 8} J$

$1.35 \times 1 0^{- 8} J$

Electrostatic energy $U = \frac{1}{2} C V^{2}$
$= \frac{1}{2} (15 \times 1 0^{- 12}) \times (60)^{2}$
$= \frac{1}{2} \times 15 \times 36 \times 1 0^{- 12} \times 1 0^{2}$
$= 270 \times 1 0^{- 10}$
$= 2.70 \times 1 0^{- 8} J$

Q. A 15pF capacitor is connected to a 60V battery. How much electrostatic energy is stored?

2.77×10−8J

1.77×10−8J

2.35×10−8J

1.35×10−8J